retval = oTrend.SetValueByTime(vData, sWhat, tTime, nTimeType, sParam)
|vData||(Variant) Value or array of values. The number of values unambiguously refers to the number of variables entered to the sWhat parameter. The order of variable in the sWhat string specified the order of values in the vData array if more variables are defined in the sWhat string. If sWhat includes only one variable, there is either a single value or an array with one item in vData.|
|sWhat||(String) Specification of the variable (or variables) whose stored value(s) has to be passed. It is possible to enter, for example, "a1;" or "a1;a2;a3;" if there has to be written into the array of the variables from the Data page. |
At the variables it is necessary to keep the order by the order from the page. For example, if the order of the variables from the page is a1,a2,a3,..., then it is possible to enter, for example, "a1;a3;" in the parameter but "a3;a1" is wrong.
|tTime||(Date) Time whose record of variables values has to be searched.|
|nTimeType||(Long) Time type of the tTime parameter|
1 - tTime is "local time" (the "standard time" in the standard season and the "daylight-saving time" in the daylight-saving season, corresponds to the computer time according to the local settings)
2 - tTime is "standard time" (in the daylight-saving and standard seasons).
|sParam||(String) Way of searching the time specified in the tTime parameter.|
"eq:xxx" - Record whose time mark equals the tTime time, is searched. The string xxx specifies the precision of the equality. For xxx the values Nsec, Nmin are enabled where N is a real number that sets the number of seconds, respectively number of minutes. If, for example, 15 seconds (...,14:00,14:15,14:30,...) values are stored by the PmTrend object, then after entering tTime=14:17, sParam="eq:3sec", the record of variables with the time mark 14:15 will be found.
Dim vData, tTime
vData = Array(10,20)
If oTrend.SetValueByTime(vData, "a0;a1", tTime, 1, "eq:1sec") Then
'variables a0,a1 are overwritten by values 10,20 successfully.